Q.4 Show that any positive odd integer is of the form 6q + 1 or, 6q + 3 or, 6q + 5 where q is some

R D Sharma Math Solutions Class 10  

Sol: Let a is any positive integer, and let b = 6

By applying Eulid's Division Lemma,
we get a = bq + r then the r can be 0 , 1, 2, 3, 4, 5.

Possible values of a = 6q, or 6q+ 1 or 6q+ 2 or 6q + 3 or 6q + 4 or 6q + 5
6q, 6q+2, 6q+4 are divisible by 2.
But 6q+1, 6q+3 or 6q+5 are not divisible by 2.
Hence 6q + 1, 6q + 3 and 6q + 5 are the odd positive inteters

Real numbers Exercise 1.1 question 2: If a and b are two positive integers such that a>b

R D Sharma Maths Solutions Class 10 Chapter 4 Exercise Q 14

R D Sharma Maths Solutions Class 10 Chapter 4 Exercise Q 14